Can someone help with number 6?

There are a couple of ways to do this, depending on the form of the result you want. You can divide by the coefficient of h, then add the opposite of the constant on the side of the equation with h. Or, you can do these steps in reverse order.
... A/(2πr) = r + h . . . . divide by h coefficient
... h = A/(2πr) - r . . . . first approach
___
... (A - 2πr²) = 2πrh . . . . . . subtract the non-h term
... h = (A - 2πr²)/(2πr) . . . . second approach