Smaller diagonal is 4.453 and longer diagonal is 10
If the two sides of a parallelogram are a and b and acute angle between the sides is θ,
the smaller diagonal is √a2+b2−2abcosθ
and longer diagonal is √a2+b2+2abcosθ
Hence in the given case
Smaller diagonal is √3.72+6.82−2×3.7×6.8×cos48∘
= √13.69+46.24−50.32×0.66913
= √59.93−40.101
= √19.829
= 4.453
Longer diagonal is √3.72+6.82+2×3.7×6.8×cos48∘
= √13.69+46.24+50.32×0.66913
= √59.93+40.101
= √100.031
= 10
