in a constant pressure calorimeter experiment a student measures a temperature change of 2.5 degrees C. The heat measured was 2.200 kJ. What was the volume of the solution?
Assume that Csol=4.18 j/gC

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The volume of the solution was 210 mL.

q = mCₛₒₗΔT

m = q/(CₛₒₗΔT) = 2200 J/(4.18 J·°C⁻¹g⁻¹ × 2.5 °C) = 210 g  

If the solution has the same density as water (1.00 g·mL⁻¹) ,

Volume = 210 g × (1 mL/1.00 g) = 210 mL

Note: The answer can have only two significant figures because that is all you gave for the temperature change.

210 mL is the volume of the solution when a constant pressure calorimeter experiment a student measures a temperature change of 2.5 degrees Celcius.

What is specific heat capacity?

The specific heat capacity is defined as the quantity of heat (J) absorbed per unit mass (kg) of the material when its temperature increases by 1 K (or 1 °C), and its units are J/(kg K) or J/(kg °C).

The volume of the solution was 210 mL.

q = mCΔT

m = q  ÷  (CΔT)

= 2200 J ÷ (4.18 J·°C⁻¹g⁻¹ × 2.5 °C)

= 210 g  

If the solution has the same density as water (1.00 g·mL⁻¹)

Volume = 210 g × (1 mL ÷ 1.00 g)

= 210 mL

Hence, 210 mL is the volume of the solution.

Learn more about the specific heat capacity here:

https://brainly.com/question/1747943

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