Here is your answer:
First you need to change the mixed numbers into improper fractions:
- [tex]-3\frac{5}{9} = \frac{-32}{9}[/tex]
- [tex]5\frac{1}{3} = \frac{16}{3}[/tex]
- Now divide:
- [tex]\frac{-32}{9} \div \frac{16}{3}[/tex]
- Use KCF:
- [tex]\frac{-32}{9} \times \frac{3}{16}[/tex]
- Now solve:
- [tex]\frac{-32}{9} \times \frac{3}{16} = \frac{96}{144}[/tex]
- Reduce:
- [tex]\frac{96}{144} \div 2 = \frac{48}{72} \div 2 = \frac{24}{36} \div 2 = \frac{12}{18} \div 2 = \frac{6}{9} \div 3 = \frac{2}{3}[/tex]
- [tex]= \frac{-2}{3}[/tex]
Therefore the answer is "-2/3."
Hope this helps!
