Respuesta :
Force of gravity along the inclined plane
[tex]F_x = F_g sin\theta[/tex]
here we have
[tex]F_g = 112.1 N[/tex]
[tex]\theta = 42 degree[/tex]
now we have
[tex]F_x = (112.1 N)sin42[/tex]
[tex]F_x = 75 N[/tex]
so here we require 75 N force along the incline to move the box upwards