Convert the 6 1/3 tons into an improper fraction:
6 1/3 = 19/3 tons.
Divide 19/3 tons by 3/4 tons per load:
19/3 / 3/4 = 19/3 * 4/3 = 76/9 = 8.4, so it will take 9 trips.
Answer: There are approximately 9 loads.
Step-by-step explanation:
Number of tons the cement weigh is given by
[tex]6\dfrac{1}{3}\ tons\\=\dfrac{19}{3}[/tex]
Weight of each load = [tex]\dfrac{3}{4}\ tons[/tex]
So, Number of tons is given by
[tex]\dfrac{\text{Weight of cement}}{\text{weight of each load}}\\\\=\dfrac{\dfrac{19}{3}}{\dfrac{3}{4}}\\\\=\dfrac{19}{3}\times \dfrac{4}{3}\\\\=\dfrac{76}{9}\\\\=8.4\\\\\approx 9\ loads[/tex]
Hence, there are approximately 9 loads.
