Respuesta :
The reaction between mercury (Hg) and sulfur (S) to form HgS is:
Hg + S ------------- HgS
Therefore: 1 mole of Hg reacts with 1 mole of S to form 1 mole of HgS
The given mass of Hg = 246 g
Atomic mass of Hg = 200.59 g/mol
# moles of Hg = 246 g/ 200.59 gmol-1 = 1.226 moles
Based on the reaction stoichiometry,
# moles of S that would react = 1.226 moles
Atomic mass of S = 32 g/mol
Therefore, mass of S = 1.226 moles*32 g/mole = 39.23 g
39.2 g of sulfur would be needed to react completely with 246 g of Hg to produce HgS
39.3 grams of sulfur reacted completely with 246 grams of mercury to form HgS.
FURTHER EXPLANATION
To solve this problem, first write the balanced chemical equation for the given reaction:
Hg + S → HgS
To solve the problem, we use the stoichiometric ratios of mercury and sulfur.
First, convert the mass of mercury to moles using the molar mass (200.59 g/mol).
[tex]moles \ Hg = 246 \ g \ Hg \times \frac{1 \ mol \ Hg}{200.59 \ g}\\\\moles \ Hg = 1.226 \ mol[/tex]
Now, determine the moles of sulfur formed using the stoichiometric ratio of sulfur and mercury which is 1:1
[tex]moles \ S \ = 1.226 \ mol \ Hg \times \frac{`1 \ mol \ S}{1 \ mol \ Hg} \\\\moles \ S = 1.226 \ mol[/tex]
To get the mass of sulfur that reacted with mercury to form HgS, use the molar mass of sulfur (32.06 g/mol)
[tex]mass \ of \ S = 1.226 \ mol \ S \times \frac{32.06 \ g}{1 \ mol \ S}\\\\\boxed {mass \ of \ S = 39.31 \ g}[/tex]
Since the given only has 3 significant figures, the final answer must also have the same. Therefore,
[tex]\boxed {\boxed {mass \ of \ S = 39.3 \ g}}[/tex]
Learn More
- Learn more about dimensional analysis brainly.com/question/1557970
- Learn more about Limiting Reactants https://brainly.com/question/12979491
Keywords: stoichiometry, dimensional analysis
