Respuesta :
Given data:
Diameter of the gold wire (d) = 0.175 cm
Length of the gold wire (l) = 1.00 * [tex]10^{5}[/tex] cm
Volume of the given gold wire = volume occupied by a cylindrical object\
= π * [tex]r^{2}[/tex]*l
here r = radius of the cross section
where : r = d/2
Hence the volume V = π * [tex](d/2)^{2}[/tex]*l
= [tex]3.142 * (0.175/2)^{2} * 1.00*10^{5} = 2.41 * 10^{3} cm^{3}[/tex]
Density of gold = 19.3 g/cm3
Weight of the gold wire = Density * volume
= [tex]19.3 g/cm^{3}[/tex] * [tex]2.41*10^{3} cm^{3}[/tex]
= [tex]4.65 * 10^{3} g = 4.65 kg[/tex]
