The space occupied by atom and nucleus would be depend on the ratio of volume of each nucleus and atom.
We known that,
[tex]Volume of sphere = \frac{4}{3}*\pi r^{3}[/tex]
Given,
[tex]Radius of nucleus(r_{n}) = 10^{-13} cm[/tex]
[tex]Radius of atom(r_{a}) = 52.9 pm = 52.9*10^{-10} cm[/tex]
Thus,
[tex]Fraction of the space = \frac{(10^{-13})^3 }{(52.9*10^{-10})^3 } = 6.8*10^{-15}[/tex]