angular speed of the Ferris wheel is given as
[tex]\omega = \frac{2\pi}{T}[/tex]
[tex]\omega = \frac{2\pi}{37.3} rad/min[/tex]
[tex]\omega = 0.17 rad/min = 2.8 * 10^{-3} rad/s[/tex]
So the angle rotated by the point in 8.60 min is given as
[tex]\theta = \omega*t [/tex]
[tex]\theta = 0.17 * 8.60 = 1.462 rad = 83.8 degree[/tex]
now the tangential velocity is given by
[tex]v = R\omega = \frac{183}{2}*2.8 * 10^{-3} = 0.26 m/s[/tex]
now the change in velocity is given as
[tex]\Delta v = 2vsin\frac{\theta}{2}[/tex]
[tex]\Delta v = 2*0.26 * sin\frac{83.8}{2}[/tex]
[tex]\Delta v = 0.35 m/s[/tex]
now the average acceleration is given as
[tex]a = \frac{\Delta v}{\Delta t}[/tex]
[tex]a = \frac{0.35}{8.6*60} = 6.73 * 10^{-3} m/s^2[/tex]
so above is the average acceleration
