Respuesta :
Energy of photon is equal to the product of Planck's constant (h) and frequency[tex]\nu[/tex].
The mathematical expression is :
[tex]E=h\nu[/tex]
where,
E = energy of photon
h = Planck's constant ([tex]6.626\times 10^{-34}Js[/tex])
[tex]\nu[/tex] = frequency of light ([tex]7.35 \times 10^{14} Hz[/tex])
Plug in the values,
[tex]E=(6.626\times 10^{-34}Js)\times (7.35 \times 10^{14} Hz)[/tex]
= [tex]48.7011 \times 10^{-20} JsHz[/tex]
Now, Hz = inverse of second
Energy of photon = [tex]48.7011 \times 10^{-20} J[/tex] or [tex]4.87011 \times 10^{-19} J[/tex]
Thus, energy of photon is equal to [tex]4.87011 \times 10^{-19} J[/tex]
Solution:
According to the formula of energy we know that
E = hf, where h is Planck's constant,
6.63×10−34 J•s. This calculation is for one photon.
E = 4.873 * 10^ -19 J.
This is the required energy for one Photon.
