The mass of a molecule of penicillin is 10^-18 kilogram and the mass of a molecule of insulin is 10^-23 kilogram. How many times greater is the mass of a molecule of penicillin than the mass of a molecule of insulin?

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sqdancefan sqdancefan · Answer 1 · 2018-09-12T09:02:30+02:00

[tex]\dfrac{\text{mass of penicillin}}{\text{mass of insulin}}=\dfrac{10^{-18}\,kg}{10^{-23}\,kg}=10^{-18-(-23)}=10^{5}[/tex]

The mass of a molecule of penicillin is 10⁵ times that of a molecule of insulin.

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JeanaShupp JeanaShupp · Answer 2 · 2019-09-10T04:54:53+02:00

Answer: [tex]10^{5}[/tex] times

Step-by-step explanation:

Given : The mass of a molecule of penicillin is [tex]10^-18[/tex] kilogram.

The mass of a molecule of insulin is [tex]10^-23[/tex] kilogram.

Now, the number of times the mass of a molecule of penicillin is greater than the mass of a molecule of insulin :-

[tex]\dfrac{10^{-18}}{10^{-23}}[/tex]

Using law of exponent :

[tex]\dfrac{a^m}{a^n}=a^{m-n}[/tex]

we have,

[tex]\dfrac{10^{-18}}{10^{-23}}=10^{-18-(-23)}=10^{-18+23}=10^{5}[/tex]

Hence, the mass of a molecule of penicillin is [tex]10^{5}[/tex] times greater than the mass of a molecule of insulin.