Respuesta :
To find the value of the energy of one photon of electromagnetic radiation, we use the equation,
[tex]E = h \nu = \frac{h c}{\lambda}[/tex]
Here, E is the energy of photon , [tex]\nu[/tex] is the frequency of the light , c is the speed of light and its value of [tex]3 \times 10 ^8 m/s[/tex],[tex]\lambda[/tex] is the wavelength of the electromagnetic radiation and h is plank constant and its value of [tex]6.626 \times 10^{-34} J .s[/tex].
Given [tex]\lambda = 575 \ nm = 575 \times 10^{-9} \ m[/tex] .
Substituting the values in above equation, we get
[tex]E=\frac{6.626 \times 10^{-34} J.s \times3 \times 10 ^8 m/s }{575 \times 10^{-9} \ m} = 3.45 \times 10^{-19} \ J[/tex]
Thus, the energy of one photon of electromagnetic radiation is [tex]3.45 \times 10^{-19} J[/tex].
The energy carried by a single photon is referred to as photon energy. the energy of one photon of electromagnetic radiation is 3.45×10⁻¹⁹J.
What is the energy of a photon?
The energy carried by a single photon is referred to as photon energy. The photon's electromagnetic frequency is directly proportional to the amount of energy it contains,
The wavelength is inversely proportionate. The greater the frequency of a photon, the more energy it has.
The given data in the problem will be;
λ is the wavelength of electromagnetic radiation=575 nM=575×10⁻⁹m
c is the speed of light=3×10⁸ m/sec
E is the energy of photons=?
We use the equation to calculate the energy of a single photon of electromagnetic radiation.
[tex]E=hv=h\frac{c}{\lambda}[/tex]
[tex]\rm E=h\frac{c}{\lambda} \\\\ E=6.6\times10^{-34}\times \frac{3\times10^8}{575\times10^{-9}}\\\\ \rm E=3.45\times10^{-19}J[/tex]
Hence the energy of one photon of electromagnetic radiation is 3.45×10⁻¹⁹J.
To learn more about the energy of photons refer to the link;
https://brainly.com/question/19795551
