Respuesta :
The molecular formula of barium phosphate is Ba3(PO4)2. This is because, barium (Ba) is has +2 charge and the phosphate group (PO4) has a -3 charge.
Therefore, 1 mole of Ba3(PO4)2 has 3 moles of Ba2+ and 2 moles of PO4(3-)
Now:
1 mole of Ba2+ has [tex]6.023*10^{23}[/tex]Ba2+ ions
Therefore, 3 moles of Ba2+ would correspond to : 3*6.023*[tex]10^{23} = 1.807*10^{24}[/tex] Ba2+ ions
Answer : The number of barium ion is, [tex]18.066\times 10^{23}[/tex]
Explanation :
The formula of barium phosphate is, [tex]Ba_3(PO_4)_2[/tex]
Barium phosphate is formed from three barium ion and 2 phosphate ion by criss-cross method. That means,
1 mole of barium phosphate dissociates to give 3 moles of barium ion and 2 moles of phosphate ion.
Or,
As we know that, 1 mole contains [tex]6.022\times 10^{23}[/tex] number of ions.
1 mole of barium phosphate dissociates to give [tex]3\times 6.022\times 10^{23}[/tex] moles of barium ion and [tex]2\times 6.022\times 10^{23}[/tex] moles of phosphate ion.
The number of barium ion = [tex]3\times 6.022\times 10^{23}=18.066\times 10^{23}[/tex]
The number of phosphate ion = [tex]2\times 6.022\times 10^{23}=12.044\times 10^{23}[/tex]
Hence, the number of barium ion is, [tex]18.066\times 10^{23}[/tex]
