Initial velocity = [tex]\(v_0\)[/tex]
acceleration in the downward direction = -9.8 [tex]\(\frac {m}{s^2}\)[/tex]
Final velocity at the highest point = 0
Maximum height reached = 0.440 m
Now, Using third equation of motion:
[tex]\(v^2 = {v_0}^{2} + 2aH[/tex]
[tex]\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.440[/tex]
[tex]\({v_0}^{2} = 2 \times 9.8 \times 0.440\)[/tex]
[tex]\(v_0 = 2.936 \frac {m}{s}\)[/tex]
Velocity with which the flea jumps = [tex]\(2.936 \frac {m}{s}\)[/tex]
