Respuesta :
The balanced chemical reaction is given as:
[tex]2NaN_{3}(s)\rightarrow 2Na(s)+3N_{2}(g)[/tex]
Now, convert [tex]19.0 ft^{3}[/tex] into litres.
[tex]1 ft^{3} = 28.3168[/tex]
So, [tex]19.0 ft^{3} = 19\times 28.3168 = 538.0192 L[/tex]
Density is equal to the ratio of mass to the volume.
[tex]D=\frac{M}{V}[/tex]
where, M = mass and V= volume [tex](538.0192 L)[/tex]
Substitute the value of density and volume in formula to get the value of mass.
[tex] 1.25 g/L=\frac{M}{538.0192 L}[/tex]
[tex] 1.25 g/L\times 538.0192 L= M [/tex]
[tex] Mass = 672.524 g [/tex]
Now, number of moles of [tex]N_{2}[/tex] gas=[tex]\frac{672.524 g}{28.02 g/mol}[/tex]
= [tex]24.00 moles[/tex]
According to the reaction, 2 moles of sodium azide gives 3 moles of nitrogen gas.
Now, in 24.00 moles of nitrogen gas produced from= [tex]\frac{2 moles of sodium azide}{3 moles of nitrogen gas}\times 24.00 moles[/tex] of nitrogen gas, moles of sodium azide.
number of moles of sodium azide = [tex]16 moles[/tex]
Mass of sodium azide in g = [tex]number of moles\times molar mass of sodium azide[/tex].
= [tex]16 moles\times 65.00 g/mol[/tex]
= [tex]1040 g[/tex]
Thus, mass of sodium azide which is required to produce [tex]19.0 ft^{3}[/tex] of nitrogen gas = [tex]1040 g[/tex]
