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Agent Hunt transferred classified files from the CIA mainframe onto his flash drive. The drive had some files on it before the transfer, and the transfer happened at a rate of 4.4, megabytes per second. After 32 seconds, there were 384 megabytes on the drive. The drive had a maximum capacity of 1000 megabytes.

How full was the drive when the transfer began?
______ megabytes


How long from the time that Agent Hunt started the transfer did it take the drive to be completely full?

______ seconds

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Part a.

The drive had some files before the transfer. We don't know the number of megabytes already on the drive, so we call it x. x is the number of megabytes on the flash drive before Agent Hunt started the transfer.

He transferred files at a rate of 4.4 megabytes per second for 32 seconds. That gives a total of 4.4 Mb/sec * 32 sec = 140.8 transferred megabytes.

He ended up with 384 megabytes.

x + 140.8 = 384

Now we can solve for x, the number of megabytes originally on the flash drive.

x = 384 - 140.8

x = 243.2

The flash drive has 243.2 megabytes when the transfer began.

Part a. Answer: 243.2 megabytes

Part b.

The total capacity if the flash drive is 1000 megabytes. He already had 243.2 megabytes on it before this transfer. 1000 Mb - 243.2 Mb = 756.8 megabytes

The flash drive has capacity for an additional 756.8 megabytes when he started the transfer. The rate of transfer is 4.4 megabytes/second.

756.8/4.4 = 172

Part b. Answer: 172 seconds

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