we are given
[tex]\frac{(x+4)}{-3x^2+12x+36}[/tex]
we know that
values of x excluded when that value of x makes f(x) undefined
and any function is undefined when it's denominator becomes 0
so, we set denominator =0
and then we solve for x
[tex]-3x^2+12x+36=0[/tex]
we can factor out
[tex]-3(x^2-4x-12)=0[/tex]
[tex](x^2-4x-12)=0[/tex]
[tex](x-6)(x+2)=0[/tex]
we get
[tex](x-6)=0[/tex]
[tex]x=6[/tex]
[tex](x+2)=0[/tex]
[tex]x=-2[/tex]
so, excluded values are
[tex]x=-2,x=6[/tex]..............Answer
