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the length of a rectangle is 2 feet less than 3 times the width. the perimeter is 68 yards. find the length and the width

Respuesta :

First you'd change the 68 yards to 194 feet. then you would make the equation (3x-2)+(3x-2)+x+x=204 because the length is 2 feet less than 3 times the width (x). when you combine like terms it is 8x-4=204. then you'd move the -4 over to the 204 to make it 8x=208. x=26 feet. then you plug it back in time find the length is 76 feet.

The length of the rectangle : 76 ft

The width of the rectangle : 26 ft

What is rectangle?

"A rectangle is a quadrilateral in which all the angles are equal (90°) and the opposite sides are equal and parallel."

Formula to calculate the perimeter of rectangle:

[tex]P=2(l+w)[/tex]

here, [tex]l[/tex] represents the length of rectangle

[tex]w[/tex] represents the width of rectangle

[tex]P[/tex] represents the perimeter of rectangle

For given situation,

Perimeter of rectangle [tex]=68[/tex] yards which is nothing but 68 × 3 feet

So, the perimeter of rectangle [tex]P=204[/tex] ft

Let, [tex]l[/tex] represents the length of a rectangle and [tex]w[/tex] represents the width of a rectangle.

The length of a rectangle is 2 feet less than 3 times the width.

⇒ [tex]l=3w-2[/tex]

Perimeter of rectangle is,

[tex]P=2(l+w)[/tex]

⇒ [tex]204=2((3w-2)+w)[/tex]

⇒ [tex]204=2(3w-2+w)[/tex]

⇒ [tex]102=4w-2[/tex]

⇒ [tex]4w=104[/tex]

⇒ [tex]w=26[/tex] ft

And [tex]l=3(26)-2[/tex]

⇒[tex]l=76[/tex] ft

Hence, the length of the rectangle is 76 ft and the width of rectangle is 26 ft.

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