We have been given that in 1983, the per capita consumption was 39.7 pounds, and in 1989 it was 47 pounds.
Let us assume t=0 corresponds to year 1980.
Hence, we can express the given information as ordered pairs as (3,39.7) and (9,47).
We can to find a linear function passing through these points. Let us first find slope of the linear function:
[tex]m=\frac{y_{2}-y_{1} }{t_{2}-t_{1}} =\frac{47-39.7}{9-3} =\frac{7.3}{6} =\frac{73}{60}[/tex]
We can write the required linear function as:
[tex]y-39.7=\frac{73}{60}(t-3)[/tex]
Upon simplifying this, we get:
[tex]y=\frac{73}{60}t+\frac{721}{20}[/tex]
In order to find per capita consumption in 1995, we need to substitute t=15 in this function.
[tex]y=\frac{73}{60}(15)+\frac{721}{20}=54.3[/tex]
Therefore, we would expect the per capita consumption of chicken in 1995 to be 54.3.