solution:
[tex]Let frictional forces due to both hands and feets be "Ff" each(since its given that they all are equal), acting in upward direction( in opposite direction of supposed motion).\\ Then since there is no motion of gymnast thus net frictional force due to both hands and feets will be exactly balanced by the weight of the gymnast,\\ i.e\\ 4f_{f}=weight =mg\\ f_{f}=\frac{55x9.8}{4}\\ =134.75N[/tex]
