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You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. Your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 10 m/s2 .

Respuesta :

speed of the car is given on the road

[tex]v = 22 m/s[/tex]

reaction time is given as

[tex]t = 0.50 s[/tex]

now we can find the distance that it will move during this reaction time

[tex]d_1 = 22* 0.50 = 11 m[/tex]

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

[tex]v_f^2 - v_i^2 = 2 a d[/tex]

[tex]0^2 - 22^2 = 2*(-10)*d[/tex]

[tex]d = 24.2 m[/tex]

so the total distance that it require to stop is given as

[tex]d = 24.2 + 11 = 35.2 m[/tex]

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer


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