Let x be total hours of battery life. We have been given that battery life of Vera's phone is down to 2/5. So remaining battery life,
[tex]1-\frac{2}{5}=\frac{5-2}{5}=\frac{3}{5}[/tex]
We have been also given that it drains another 1/9 every other hour. Now let us substitute our given information into an equation.
[tex]\frac{1}{9}\cdot x=\frac{3}{5}[/tex]
Now we will solve for x.
[tex]x=\frac{3\cdot 9}{5}=\frac{27}{5}[/tex]
[tex]x=(5+\frac{2}{5})hours[/tex]
Let us convert 2/5 into minutes. We know 1 hour has 60 minutes.
[tex]60\cdot \frac{2}{5}=24\text{minutes}[/tex]
Therefore, remaining battery life will be 5 hours and 24 minutes.
