Respuesta :
Answer;
= 5.45 × 10-3 g or 5.45 mg
Explanation;
1 meter = 3.048 feet
Volume = 10.6 × 14.8 × 20.5 ft³ × (1/3.048 ft/m³)
= 113.57 m³
Therefore; the mass of carbon monoxide;
= 113.57 m³ × 48 × 10^-6 g/m³
= 5.45 × 10^-3 g
= 5.45 mg
Answer:
m = [tex]4.37 * 10^{-3}[/tex] g
Explanation:
Volume = 10.6 × 14.8 × 20.5 ft = 3216.04 ft³
1 feet³ = 0.0283168 meter ³
Now convert feet³ to meter³
Volume = 3216.04 ft³ × (3.048/1 m³/ft³) = 91.06811131 m³
This question gives the density as 48μg/m3
μ = [tex]10^{-6}[/tex]
The formula for density is [tex]p = \frac{m}{V}[/tex]
[tex]48*10^{-6} = \frac{m}{91.06811131}[/tex]
Solve for m
m = [tex]4.37 * 10^{-3}[/tex] g
