Given the density of ethanol = 0.79[tex]\frac{g}{cm^{3} }[/tex]
Volume of ethanol = 75.0 mL
Calculating the mass if ethanol from density and volume:
[tex]75.0 mL * \frac{0.79g}{1cm^{3} } *\frac{1cm^{3} }{1mL}=59.25g[/tex]
Molar mass of ethanol = (2*atomic weight of C)+(6*atomic weight of H)+(1*atomic weight of O)
=(2*12g.mol) + (6*1g/mol) + (1*16g/mol)
=46g/mol
Moles of ethanol = [tex]59.25 g *\frac{1 mol}{46g} =1.288 mol[/tex]
Volume of the solution = 250.0 mL
Converting the volume from mL ot L:
[tex]250.0mL*\frac{1L}{1000mL}=0.2500L[/tex]
Molarity of ethanol in the solution = [tex]\frac{1.288mol}{0.250L} =5.15 M[/tex]
5.15 m is the molarity of the ethanol in the given 250 mL solution.
Molarity of any solution will be calculated as:
M = n/V, where
n = no. of moles
V = volume
Given volume of solution = 250mL = 0.25L
Moles of ethanol will be calculated as:
n = W/M, where
M = molar mass of ethanol = 46g/mol
W = given mass, this will be calculated by using the below formula:
Density = mass/volume,
Density of ethanol = 0.79 g/cm3 = 0.79 g/mL (given)
Volume of ethanol = 75mL
Mass of ethanol = 0.79g/mL × 75mL = 59.25g
On putting values on the moles equation we get,
Moles of ethanol = 59.25g / 46g/mol = 1.288 moles
Now, molarity of ethanol will be calculated as:
M = 1.288moles / 0.250L = 5.15M
Hence, the molarity of ethanol is 5.15M.
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