Answer;
= 520.833 m
Explanation and solution;
Assuming D is at 25 m/s; T's acc = 2.4 m/s2
let time be t and distance be d
for D,
25 × t = d
t = d/25 ----(1)
for T,
u=0
s= ut + 0.5 at^2
d = 0 + 0.5 × 2.4 × t^2
d = 1.2 t^2 ----(2)
(1) sub into (2)
d = 1.2 × [d/25]^2
d = 0.00192 d^2
d = 520.833 m