Answer:
C₃H₈
Solution:
Step 1: Calculating Moles for each Element:
C = Mass of CO₂ × (1 mol of CO₂÷ M.Mass of CO₂) × (1 mol of C ÷ 1 mol of CO₂)
C = 2.641 g × (1 mol of CO₂÷ 44.011 g.mol⁻¹) × (1 mol of C ÷ 1 mol of CO₂)
C = 0.0600 mol
H = Mass of H₂O × (1 mol of H₂O ÷ M.Mass of H₂O) × (2 mol of H ÷ 1 mol of H₂O)
H = 1.442 g × (1 mol of H₂O ÷ 18.106 g.mol⁻¹) × (2 mol of H ÷ 1 mol of H₂O)
H = 0.159 mol
Step 2: Calculate the Smallest whole number ratio as,
C H
0.0600 0.159
0.0600/0.0600 0.159/0.0600
1 2.654
Multiply ratio by 3,
3 7.96
Or,
3 ≈ 8
Result:
Empirical Formula of Propane is C₃H₈