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For the bake sale, Helen made cookies and brownies. The cookies sold for 95 cents, and the brownies sold for 60 cents. If she baked 31 items that sold for $23.85, how many of each dessert did she sell?

Respuesta :

Let us suppose that 'm' cookies and 'n' brownies were baked.

Since, Helen baked 31 items in total.

So, m+n = 31 (Equaion 1)

So, m = 31-n

Now, since cookies are sold for 95 cents, and the brownies sold for 60 cents.

Since, 1 $ = 100 cents

So, cookies are sold for $0.95, and the brownies sold for $0.60.

Helen sold the cookies and brownies at $23.85

So, 0.95m + 0.60n = 23.85 (Equaion 2)

Substituting the value of 'm' in equation 2, we get as

[tex]0.95(31-n)+0.60n = 23.85[/tex]

29.45 - 0.95n +0.60n = 23.85

-0.35n = -5.6

So, n = 16

Since, m = 31-n

m = 31-16

m = 15

So, Helen sold  15 cookies and 16 brownies.

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