We use kinematic equation,
[tex]v^2_{f} = v^2_{0} + 2 a s[/tex]
Here, [tex]v_{f}[/tex] is final velocity and a is acceleration and s is maximum height.
Given, [tex]s = 0.470 \ m[/tex] and we take a as negative value of acceleration due to gravity [tex]( - 9.8 \ m/s^2)[/tex].
At the maximum height, final velocity is zero.
Substituting these values in above equation, we get
[tex]0 = v^2_{0} + 2(-9.8 \ m/s^2)0.470 \ m \\\\ v^2_{0} = 9.2 (m/s)^2 \\\ v_{0} = 3.03 m/s[/tex]
Therefore, the initial velocity with it leave the ground is 3.03 m/s.
Based on the data provided, the initial velocity of the flea is 3.036 m/s
The initial velocity, final velocity and height attained by the flea as it jumps straight up and the acceleration due to gravity are related by the formula below:
Where
At maximum height, v = 0
Solving for u:
[tex]u = \sqrt{2gh} [/tex]
[tex]u = \sqrt{2 \times 9.81 \times 0.470} [/tex]
[tex]u = 3.036 \: m {s}^{ - 1} [/tex]
Therefore, the initial velocity of the flea is 3.036 m/s
Learn more about initial velocity at: https://brainly.com/question/14903584
