If a flea can jump straight up to a height of 0.410 m , what is its initial speed as it leaves the ground?

Respuesta :

Initial velocity = [tex]\(v_0\)[/tex]

acceleration in the downward direction = -9.8 [tex]\(\frac {m}{s^2}\)[/tex]

Final velocity at the highest point = 0

Maximum height reached = 0.410 m

Now, Using third equation of motion:

[tex]\(v^2 = {v_0}^{2} + 2aH[/tex]

[tex]\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.410[/tex]

[tex]\({v_0}^{2} = 2 \times 9.8 \times 0.410\)[/tex]

[tex]\(v_0 = 2.834 \frac {m}{s}\)[/tex]

Speed with which the flea jumps = [tex]\(2.834 \frac {m}{s}\)[/tex]