Solution:
Here the place value of digit 3 in the number 234,492 can be found using its position.
Here 3 is at 10,000th place so the value of digit 3 in the given number is 30,000.
Now we are supposed to create a number in which the digit 3 is 100 times less than the 3 in 234,492.
So we will just change the place of the digit 3.
So we get 244,392.
Here the place value of 3 is 300 because 3 is at 100th position.
Verify: [tex]\frac{30,000}{300}=100[/tex]
Hence the required number is 244,392.