solution:
long to travel 19.6m at 28m/s
t =19.6/28
=time taken to drop from rest
s=ut+(1/2)at^2
u=0
a=~10
so s=(1/2)*10*(19.6/28)^2 =2.45m
The tennis ball is "2.401 m" far.
According to the question,
Horizontal distance = 19.6 m
Horizontal speed = 28
The time taken by the ball be:
→ t = [tex]\frac{Horizontal \ distance}{Horizontal \ speed}[/tex]
By substituting the values,
= [tex]\frac{19.6}{28}[/tex]
= [tex]0.7[/tex] second
By using equation of motion, we get
→ s = ut + [tex]\frac{1}{2}[/tex] gt²
By substituting the values,
= [tex]0+0.5\times 9.8\times (0.7)^2[/tex]
= [tex]2.401[/tex] m
Thus the above answer is right.
Find out more information about Equation of motion here:
https://brainly.com/question/25951773
