speed of tortoise is given as v1 = 0.14 m/s
speed of hare is given as v2 = 20*0.14 = 2.8 m/s
now let say the total length of the path is "d"
so the total time taken by the tortoise to cover this
[tex]t = \frac{d}{0.14}[/tex]
now given that hare took rest for 1 min
so total time of run for hare is (t - 60)s
so the distance that hare covered is given by
[tex]d - 0.30 = 2.8 * (t - 60)[/tex]
now by above two equations
[tex]d - 0.30 = 2.8 * \frac{d}{0.14} - 168[/tex]
[tex]168 - 0.30 = (20 - 1)d[/tex]
[tex]d = 8.82 m[/tex]
and the time t is given by
[tex]t = \frac{8.82}{0.14}[/tex]
[tex]t = 63 s[/tex]
so part a)
t = 63 s
part b)
d = 8.82 m