[tex]n-5\cdot\dfrac{2}{3}=\dfrac{3}{4}\\\\n-\dfrac{10}{3}=\dfrac{3}{4}\ \ \ \ |\cdot12\\\\12n-12\cdot\dfrac{10}{3}=12\cdot\dfrac{3}{4}\\\\12n-4\cdot10=3\cdot3\\\\12n-40=9\ \ \ \ |+40\\\\12n=49\ \ \ \ \ |:12\\\\n=\dfrac{49}{12}[/tex]
