Respuesta :
Vi = Velocity initial = 35 m/s
Vf = Velocity final = 75 m/s
t = 5s
Equation:
Vf = Vi + at
65 = 35 + a(5)
30 = 5a
a = 6
Acceleration was 6 m/s^2
C. 6 m/s^2
Vf = Velocity final = 75 m/s
t = 5s
Equation:
Vf = Vi + at
65 = 35 + a(5)
30 = 5a
a = 6
Acceleration was 6 m/s^2
C. 6 m/s^2
The acceleration of the car traveling in the race is 6m/s².
Hence, Option C) 6m/s² is the correct answer.
Given the data in the question;
- Initial velocity; [tex]u = 35m/s[/tex]
- Final velocity; [tex]v = 65m/s[/tex]
- Time taken; [tex]t = 5s[/tex]
Acceleration; [tex]a =\ ?[/tex]
To determine the acceleration of the car, we use the first equation of motion:
[tex]v = u + at[/tex]
Where v is the final velocity, u is the initial velocity, a is the acceleration and t is time.
We substitute our given values into the equation
[tex]65m/s = 35m/s + [ a * 5s]\\\\a * 5s = 65m/s - 35m/s\\\\a * 5s = 30m/s\\\\a = \frac{30m/s}{5s}\\\\a = 6m/s^2[/tex]
The acceleration of the car traveling in the race is 6m/s².
Hence, Option C) 6m/s² is the correct answer.
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