we have
[tex]y=7x^{2}-10[/tex]
To find the inverse
Step 1
Exchanges the variables, x for y and y for x
[tex]x=7y^{2}-10[/tex]
Step 2
Isolate the variable y
[tex]x=7y^{2}-10[/tex]
[tex]7y^{2}=x+10[/tex]
[tex]y^{2}= \frac{x+10}{7}[/tex]
Square Root both sides
[tex]y=(+/-)\sqrt{\frac{x+10}{7}}[/tex]
Step 3
Let
[tex]f(x)^{-1}=y[/tex]
so
[tex]f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}[/tex]
therefore
the answer is
The inverse is
[tex]f(x)^{-1}=(+/-)\sqrt{\frac{x+10}{7}}[/tex]
