Respuesta :
In this case, the inclined plane is frictionless and therefore energy is perfectly conserved with no losses. The block originally starts off with some gravitational potential energy, which is then completely converted into kinetic energy. So the initial gravitational potential energy is equal to the final kinetic energy.
[tex] PE_{initial} = KE_{final} [/tex]
[tex] PE_{initial} =mgh=(5kg)(9.8m/ s^{2} )(0.8m)=39.2 joules[/tex]
[tex] KE_{final}=39.2joules [/tex]
[tex] PE_{initial} = KE_{final} [/tex]
[tex] PE_{initial} =mgh=(5kg)(9.8m/ s^{2} )(0.8m)=39.2 joules[/tex]
[tex] KE_{final}=39.2joules [/tex]
The physics conservation of energy E = 39.2 joules.
To calculate the Physics conservation of energy.
Mass of the block, m = 5 kg
At the top, the block will have only potential energy which is given by :
P=mgh
At the bottom of the inclined plane, it will have only kinetic energy which is given by :
E=(1/2)mv2
Applying the conservation of energy as :
E=(1/2)mv2=mgh
E=5*9.8*0.8
E = 39.2 joules.
The physics conservation of energy E = 39.2 joules.
To learn more about The physics conservation of energy refer:https://brainly.com/question/4301920
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