Respuesta :

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1s^2 2s^2 2p^6

Neon is element number 10, so a neon atom has 10 electrons.

The n = 1 shell consists of one s orbital.

The remaining eight electrons fill the n = 2 shell. The n = 2 shell consists of an s subshell with a single s orbital and a p subshell with three p orbitals.

Each orbital can hold a maximum of two electrons.

Thus, there are two 1s electrons, two 2s electrons, and six 2p electrons.

Therefore, the orbital notation (or electron configuration) of neon is

1s^2 2s^2 2p^6.