Reneeklemm
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If a swimming pool contains 2,850 kiloliters (kL) of water, how many gallons (gal) of water does it contain? (1 gal = 3.785 L)

Respuesta :

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

[tex] 1gal=3.785L [/tex]

[tex] 3.785L=1gal [/tex]

Firstly , we will find for 1L

[tex] 1L=\frac{1}{3.785}gal [/tex]

now, we can multiply both sides by 2850000

[tex] 2850000*1L=2850000*\frac{1}{3.785}gal [/tex]

[tex] 2850000L=2850000*\frac{1}{3.785}gal [/tex]

[tex] 2850000L=752972.25892gal [/tex]

so,

a swimming pool contains 752972.25892gal of water...........Answer


samueladesida43

The swimming pool contains  752, 972.26 gallons of water.

HOW TO CONVERT LITRE TO GALLON:

  • The conversion ratio between litre and gallon as given in the question is 1 gal = 3.785 L.

  • According to this question, a swimming pool contains 2,850 kiloliters (kL) of water. First, we change kiloliters to litres

1 kiloliter = 1000 litres

2,850 kiloliters = 2850 × 1000

= 2,850,000 litres.

  • Next, we convert litres to gallon

Since, 1 gal = 3.785 L

2,850,000 litres = 2,850,000 ÷ 3.785

= 752, 972.2589

= 752, 972.26 gallons.

Therefore, the swimming pool contains  752, 972.26 gallons of water.

Learn more: https://brainly.com/question/21369880?referrer=searchResults

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