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midknight9

So let's convert these to improper fractions:

[tex] 38\frac{1}{3}=\frac{115}{3} [/tex]

[tex] 2\frac{3}{5}=\frac{13}{5} [/tex]

Then let's convert these fractions so that they have a denominator of 15 so we can better compare these numbers:

[tex] \frac{115}{3}=\frac{575}{15} [/tex]

[tex] \frac{13}{5}=\frac{39}{15} [/tex]

So when we have [tex] \frac{39}{15} [/tex] gallons splash out, we are left with [tex] \frac{536}{15} [/tex] gallons or [tex] 35\frac{11}{15} [/tex] gallons in the tub.

The amount of water left in the tube is [tex]35\dfrac{11}{15}[/tex].

Given that

A bathtub is filled with 38 1/3 gallons of water.

If 2 3/5 gallons splash out.

We have to determine

How much water is left in the tube?

According to the question

A bathtub is filled with 38 1/3 gallons of water.

If 2 3/5 gallons splash out.

The amount of water left is determined by subtracting the amount of water from the amount of splash water.

Then,

[tex]= 38\dfrac{1}{3}- 2 \dfrac{3}{5}\\\\= \dfrac{38 \times 3 +1 }{3} - \dfrac{2\times 5+3}{5}\\\\ = \dfrac{114+1}{3} - \dfrac{10+3}{5}\\\\= \dfrac{115}{3}-\dfrac{13}{5}\\\\= \dfrac{115 \times 5 - 13 \times 3}{15}\\\\= \dfrac{575-39}{15}\\\\= \dfrac{536}{15}\\\\= 35\dfrac{11}{15}[/tex]

Hence, the amount of water left in the tube is [tex]35\dfrac{11}{15}[/tex].

To know more about Equation click the link given below.

https://brainly.com/question/11465228

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