Answer:Explained
Explanation:
For
3)at t=0 v=4 m/s
and t=2 v=5.2 m/s
acceleration is \frac{v-u}{t}=\frac{5.2-4}{2-0}=0.6m/s^2[/tex]
5)Constant negative acceleration because slope of the graph is negative and constant.
4)[tex]a=\frac{16-14}{11-10}[/tex]
[tex]a=2 m/s^2[/tex]
7)changing negative acceleration because slope of parabola is decreasing to zero and slope of V-t graph give acceleration
9)changing positive acceleration as the slope of graph is increasing.
10)at t=2 acceleration is [tex]-2m/s^2[/tex] because after t=4 slope is increasing and positive.
