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In the answer from Part I, each two-ace hand got counted twice. For example, A A X got counted as a separate hand from A A X. Since order should not matter in a card hand, these are really the same hand. What is the actual number of two-ace hands (combinations) you can get from a deck of 52 cards?

Respuesta :

LammettHash

Assuming exactly 3 cards are being drawn: we want 2 of them to come from the 4 available aces, and the last 1 to come from the remaining 48 non-ace cards.

[tex]\dbinom42\cdot\dbinom{48}1=\dfrac{4!}{2!(4-2)!}\cdot\dfrac{48!}{1!(48-1)!}=6\cdot48=288[/tex]

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