Respuesta :
For the equation,
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.
y = 1/2(x+3)^2 -5
The vertice is (-3,-5). Therefore the axis of symmetry is X = -3.
Answer:
the equation of the axis of symmetry for the parabola is:
[tex]x=-3[/tex]
Step-by-step explanation:
The equation of the parabola is given by:
[tex]y=-\dfrac{1}{2}(x+3)^2-5[/tex]
We know that for the general equation of the parabola of the type:
[tex]y=a(x-h)^2+k[/tex]
The vertex of the parabola is at (h,k)
and the axis of symmetry of the parabola is : x=h
Here after comparing the equation of parabola with the general equation of parabola we have:
[tex]h=-3[/tex]
Hence, the axis of symmetry of the given parabola is:
[tex]x=-3[/tex]
