32 grams of [tex] O_2 [/tex] is 1 mole.
4 grams of [tex] H_2 [/tex] is 2 moles.
So we have 2 moles of [tex] H_2O [/tex]. Each mole has approximately [tex] 6 \cdot 10^{-23} [/tex] particles. In 2 moles of water, there are [tex] 12 \cdot 10^{-23} [/tex] water molecules.
Answer:
1.2044 * 10^24 molecules
Explanation:
First thing's first. Let's bring out the balanced chemical equation.
So we have;
2H₂ + O₂ → 2H₂O
Number of moles: 2 : 1 : 2
Molar mass 2 ( 2 * 1) : 32 (2 * 16) : 18 (2 + 16)
Reacting mass 4 ( 2* 2) : 32 ( 1 * 32) : 38 (18 * 2)
Reacting mass = molar mass * number of moles
The number of moles formed when 4 grams of hydrogen reacts with 32 grams of oxygen is 2 moles.
To obtain number of molecules, multiply the number of moles by the Avogadro constant, 6.022 x 10^23.
This means; Number of Molecules = Number of moles * Avogadro's constant
Number of molecules = 2 * 6.022 * 10^23 = 12.044 * 10^23 = 1.2044 * 10^24 molecules
