So we know that the molar ration of carbon dioxide to sugar is 6:1 in the balanced equation, so we must first find how many moles of carbon dioxide 200g is.
The molar weight of carbon dioxide is 44.008g - found from the atomic weights of the elements on the periodic table.
So we must solve for moles:
[tex] 200g*\frac{1mol}{44.008g}=4.545mol [/tex]
So then we can set up a proportion to solve for how many moles of sugar were produced:
[tex] \frac{1mol_{sugar}}{6mol_{CO_{2}}}= \frac{xmol_{sugar}}{4.545mol_{CO_{2}}} [/tex]
Then we solve for x:
[tex] 6x=4.545 [/tex]
[tex] x=0.7575 [/tex]
So now we know that 0.7575 moles of sugar were produced. To convert to grams, we must know the molar weight of sugar:
[tex] 6(12.01g)+12(1.008g)+6(15.999g)=72.06g+12.096g+95.994g=180.15g [/tex]
So then we can solve for grams of sugar:
[tex] \frac{180.15g}{1mol}*0.7575mol=136.46g_{sugar} [/tex]
Therefore we know you can make 136.46 grams of sugar when using 200 grams of carbon dioxide.
