Comparing the values of the underlined digits?
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Answer:
1.The value of 3 in 6300 is 10 times the value of 3 in 530.
2. The value of 4 in 47163 is 10 times the value of 4 in 34258.
Step-by-step explanation:
We are given that
1.6300 and 530
We have to find the value of 3 in both number
The value of 3 in 6300 is 300.
It is 100 times of 3.
The value of 3 in 530 is 30.It is 10 times of 3.
Hence, the value of 3 in 6300 is 10 times the value of 3 in 530.
2.34,258 and 47,163
We have to find the value of 4 in both number
The value of 4 in 34258 is 400 which is 1000 times of 4.
The value of 4 in 47163 is 40000 which is 10000 times of 4.
Hence, the value of 4 in 47163 is 10 times the value of 4 in 34258.
The value of 3 in 6300 is ten times the value of 3 in 530 and the value of 4 in 47,163 is ten times the value of 4 in 34,258.
For example;
In the number; 13,548, the place value of the digits in the number are;
Ones -8
Tens - 4
Hundreds - 5
Thousands - 3
Ten Thousands – 1
1 x 10,000 = 10,000
3 x 1000 = 3,000
5 x 100 = 500
4 x 10 = 40
8 x 1 = 8
6,300 and 530
The value of 3 in 6,300 is 300 and
The value of 3 in 530 is 30
Therefore; the value of 3 in 6300 is ten times the value of 3 in 530
34,258 and 47,163
The value of 4 in 34,258 is 4,000 and
The value of 4 in 47,163 is 40,000.
Therefore;
The value of 4 in 47,163 is ten times the value of 4 in 34,258.
Level: Middle school
Subject: Mathematics
Topic: Place value and total value