Let's comment the system. We can see that the first equation is [tex] x+y = 27 [/tex]. It means that x and y are two quantities that sum to 27. Since we know that the team scored a total of 27 baskets, we know that x and y are something that "compose" the number of baskets. So, they must be the number of two and three points shot.
The second equation is [tex] 2x + 3y = 60 [/tex]. We know that the team scored 60 points, and that every x is "worth" 2 and every y is "worth" 3. So, x is the number of two-points shots and y is the number of three points shots.
To solve the system we can isolate y from the first equation:
[tex] y = 27-x [/tex]
and substitute this expression in the second equation:
[tex] 2x + 3y = 60 \implies 2x + 3(27-x) = 60 \implies -x = -21 \implies x = 21 [/tex]
So, we can deduce back
[tex] y = 27-x = 27-21 = 6[/tex]
Now remember that x was the number of two-points shots and y was the number of three-points shots to get to the answer.
Answer:
C) (21,6); 21 two-point shots and 6 three-point shots
Step-by-step explanation:
just did the assignment :/
