the parent function y = |x| stretched vertically by a factor of 2, shifted left 3 units and down 4 units
whats the equation?

Respuesta :

Hello!

Let's go through some formula to distinguish the changes that happen to a graph's equation when they are transformed.

Vertical shifts have this type of formula:

f(x) + k → up k units and f(x) - k → down k units

Horizontal shifts have this type of formula:

f(x + k) → left k units and f(x - k) → right k units

Reflections have this type of formula:

-f(x) → reflect over x-axis and f(-x) → reflect over y-axis

Vertical stretches have this type of formula:

a · f(x) where a > 1

Vertical compressions have this type of formula:

a · f(x) where a < 1

Horizontal stretches have this type of formula:

f(a · x) where a > 1

Horizontal compressions have this type of formula:

f(a · x) where a < 1

With that in mind, we can write our transformed absolute value function.

Since the equation is vertically stretched by a factor of 2, a = 2.

y = 2|x|

Also, since the function is shifted left 3 units, k = -3.

y = 2|x + 3|

Finally, the function is also shifted down 4 units, so k = -4.

y = 2|x + 3| - 4

Therefore, the equation is y = 2|x + 3| - 4.

A function can be transformed by stretching it and by translating it.

The equation of the transformation is: [tex]y''' = 2|x + 3| -4[/tex]

The parent function is given as:

[tex]y = |x|[/tex]

The rule of vertical stretch by 2 is:

[tex](x,y) \to (x,2y)[/tex]

So, we have:

[tex]y' = 2y[/tex]

Substitute [tex]y = |x|[/tex]

[tex]y' = 2|x|[/tex]

The rule of shifting a function left by 3 units is:

[tex](x,y) \to (x + 3,y)[/tex]

So, we have:

[tex]y'' = 2|x + 3|[/tex]

The rule of shifting a function down by 4 units is:

[tex](x,y) \to (x,y -4)[/tex]

So, we have:

[tex]y''' = 2|x + 3| -4[/tex]

Hence, the resulting function is:

[tex]y''' = 2|x + 3| -4[/tex]

Read more about transformation at:

https://brainly.com/question/13810353