kat2539 kat2539
  • 13-08-2018
  • Physics
contestada

What is the value of work done on a object when a 10-newton force moves it 30 meters and the angle between the force and displacement is 25degrees

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Rohit710
Rohit710 Rohit710
  • 13-08-2018
Hello

[tex]\bold{w = Fs*cos\theta}[/tex]

→ w = 10*30*cos25°

cos25° = 0.991203

→ Work Done = 297.360 Joule ( J )

Hope It helps You. ^_^
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