Answer:
y = x^2 + 2
Step-by-step explanation:
find the equation below whose axis of symmetry is x = 0
to find axis of symmetry we use formula x= -b/2a
WE compare the equation with the form y =ax^2 + bx+c
y = x^2 + 2x
a= 1 and b = 2 so [tex]x= \frac{-b}{2a} = \frac{-2}{2} =1[/tex]
y = x^2 − 16x + 58
a= 1 and b = -16 so [tex]x= \frac{-b}{2a} = \frac{16}{2} =8[/tex]
y = x^2 + 2
a= 1 and b = 0 so [tex]x= \frac{-b}{2a} = \frac{0}{2} =0[/tex]
y = x^2 − 4x + 2
a= 1 and b = -4 so [tex]x= \frac{-b}{2a} = \frac{4}{2} =2[/tex]
